alexbel31
Junior Member | Редактировать | Профиль | Сообщение | Цитировать | Сообщить модератору В php новичек, поэтому прошу помощи у гуру =). При установке постраничной навигации выскакивают ошибки, ниже код. Код: $result77 = mysql_query("SELECT str FROM option", $db); $myrow77 = mysql_fetch_array($result77); <<< Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in $num = $myrow77["str"]; @$page = $_GET['page']; $result00 = mysql_query("SELECT COUNT(*) FROM news", $db); $temp = mysql_fetch_array($result00); $posts = $temp[0]; $total = (($posts - 1) / $num) + 1; <<< Warning: Division by zero in $total = intval($total); $page = intval($page); if(empty($page) or $page < 0) $page = 1; if($page > $total) $page = $total; $start = $page * $num - $num; $result = mysql_query ("SELECT id,title,description,author,date FROM news ORDER BY id LIMIT $start, $num",$db); $myrow = mysql_fetch_array ($result); <<< Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in do { printf ("<table align='center' class='news'> <tr> <td class='news_title'> <p class='news_name'><a href='view_news.php?id=%s'>%s</a></p> <p class='news_adds'>Дата добавления: %s</p> <p class='news_adds'>Автор: %s</p></td> </tr> <tr> <td>%s</td> </tr> </table><br>",$myrow['id'],$myrow['title'],$myrow['date'],$myrow['author'],$myrow['description']); } while ($myrow = mysql_fetch_array ($result)); <<< Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in |
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